Algebra II · Units 1–9 · Quick reference

College Entrance Math Review(SAT · ACT · PSAT)

Grades 9–128 pages

Algebra, advanced math, problem solving and data analysis, and geometry and trigonometry, with the three test formats side by side, strategies and original practice. Not affiliated with or endorsed by any test maker. SAT, PSAT, CLEP and ACT are trademarks of their owners.

1The three tests2Strategies3Numbers4Linear5Systems6Functions7Function families8Quadratics9Exponents & polynomials10Polynomial graphs11Exponentials & logs12Ratios & percents13Word problems14Statistics15Probability & inference16Angles & triangles17Area, volume, circles18Trigonometry19Number & quantity20Formulas21Practice

1The Three Tests at a Glanceconfirm details before test day

Formats, from public information (Oct 2026)
Math sectionSATPSAT/NMSQT · PSAT 10 · PSAT 8/9ACT
Questions44 (40 scored + 4 unscored pretest)44 (40 scored + 4 unscored pretest)45 (41 scored)
Time and pace70 min: two 35-min modules (≈ 1.6 min each)same as the SAT50 min (≈ 1.1 min each)
Formatdigital, adaptive (module 2 depends on module 1); easy → hard in each modulesame as the SATpaper or online; not adaptive
Answer typesmultiple choice (4 choices) + typed answers (about 1 in 4)same as the SATmultiple choice, 4 choices
Calculatorwhole section: built-in graphing calculator or your own approved onesame as the SATyour own 4-function, scientific or graphing (no CAS); built in online
Formulasreference sheet providedreference sheet providednone given: memorize them
Math score200–800160–760; PSAT 8/9: 120–7201–36
What is tested (approximate share of scored math questions)
SAT and PSAT domainShareSeeACT reporting categoryShareSee
Algebra (linear)≈ 35 %§4–5Number & Quantity10–12 %§3, §9, §19
Advanced Math (nonlinear)≈ 35 %§6–11Algebra; Functions17–20 % each§4–11
Problem Solving & Data Analysis≈ 15 %§12–15Geometry (with trig)17–20 %§16–18
Geometry & Trigonometry≈ 15 %§16–18Statistics & Probability12–15 %§14–15
(PSAT tests: same four domains)Integrating Essential Skills≈ 20 %§3, §12–13

CLEP College Algebra (college credit)

  • About 60 questions in 90 minutes, some unscored.
  • Built-in scientific (non-graphing) calculator only.
  • Scored 20–80; ACE recommends credit at 50 (3 semester hours); colleges set their own policy.
  • Study §4–11 and §19.

Scoring facts

  • No wrong-answer penalty on any of these tests: never leave a blank.
  • SAT and PSAT modules run easy → hard: bank the early points.
  • Practice with the free full-length tests each test maker posts.

2Strategies That Workplug in, backsolve, graph it

Plug in numbers

  • When the answer choices are expressions, pick an easy value (x = 5; avoid 0 and 1), work out the target number, then test each choice.

EXWhich equals x² − 9x − 3 (x ≠ 3)? Try x = 5: 162 = 8. Only x + 3 gives 8.

Reread the last line

Before you choose, read the question’s last line again: it may want 3x, the units or the total, not x.

Backsolve

  • When the choices are numbers, start with a middle choice, test it in the problem, then go up or down.

EXA number plus 40 % of itself is 84. Try 60: 60 + 24 = 84 ✓, so the number is 60.

Use the graphing calculator

  • Equations, systems: graph each side (or each equation); read where they cross.
  • Quadratics: tap the graph for the vertex and zeros.
  • Data: enter a table and fit a line or curve.

Student-produced responses (SAT, PSAT)

  • Type a fraction or a decimal: up to 5 characters, 6 with a minus sign.
  • No mixed numbers (type 7/2, not 3 1/2), and no %, $ or commas.
  • If several answers work, enter one.

Common traps

  • Watch units and the words not, except and least.
  • Check for extraneous roots after squaring or clearing fractions.
School
Launch
Algebra II · Units 1–9: Algebra II · with Algebra I, Geometry, Statistics and Trigonometry
Lesson: schoollaunch.org/courses/algebra2/ · Original School Launch material.
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College Entrance Math ReviewAlgebra II · Units 1–9 · continued

3Numbers & Operationsthe arithmetic every test assumes

Kinds of numbers
SetMembersExample
Integers…, −2, −1, 0, 1, 2, …−7, 0, 12
Rationala ratio of integers pq (q ≠ 0)34, −2.5, 0.3̄
Irrationalnot a ratio: decimal never ends or repeats√2, π
Primeexactly two factors, 1 and itself2, 3, 5, 7, 11, 13
2 is the only even prime; 1 is not prime. Even × anything = even; odd × odd = odd.

Factors and multiples Worked

GCF(36, 60) = 12; LCM(36, 60) = 180GCF × LCM = 36 × 60
36 = 2² · 3²; 60 = 2² · 3 · 5prime factorizations
47 ÷ 6 = 7 remainder 547 = 6 · 7 + 5

Fractions and order of operations Worked

23 + 58 = 16 + 1524 = 3124common denominator
34 ÷ 910 = 34 × 109 = 56flip and multiply
20 − 3(4 − 6)² ÷ 2 = 20 − 3 · 4 ÷ 2 = 14parentheses, powers, × ÷, + −

Scientific notation

  • a × 10ⁿ with 1 ≤ a < 10.
  • Multiply: multiply the a’s, add the exponents.

EX(3 × 10⁴)(6 × 10⁻⁷) = 18 × 10⁻³ = 1.8 × 10⁻²; 0.00042 = 4.2 × 10⁻⁴.

Number sense

Absolute value
|x| is the distance from 0: |−8| = 8; |x − 3| ≤ 2 means 1 ≤ x ≤ 5
Mean of a group
total ÷ count; the total = mean × count
Digits
3,482.6: 8 is in the tens place, 6 in the tenths

4Linear Equations & Inequalitiesslope, intercepts, forms

Forms of a line
FormEquationShows
Slope-intercepty = mx + bslope m, y-intercept b
Point-slopey − y₁ = m(x − x₁)slope and one point
StandardAx + By = Cslope −AB; intercepts CA, CB
Horizontal; verticaly = k; x = hslope 0; undefined

Slope

(−1, 4) and (3, −4): m = −84 = −2, so y = −2x + 2 (x-intercept 1).

m = y₂ − y₁x₂ − x₁

xyy = −2x + 2(−1, 4)(3, −4)
Down 2 for every 1 to the right: slope −2.

Parallel and perpendicular

  • Parallel lines: equal slopes.
  • Perpendicular lines: slopes are negative reciprocals (product −1).

EXThrough (2, 5), perpendicular to y = 23x + 1: m = −32, so y = −32x + 8.

Solve Worked

2x − 13 = x + 42 → 4x − 2 = 3x + 12 → x = 14cross-multiply
−2(x − 5) ≥ 14 → x − 5 ≤ −7 → x ≤ −2dividing by −2 flips ≥
|2x − 3| = 7 → 2x − 3 = 7 or −7 → x = 5 or −2two cases

Read the meaning

Linear model
C = 45 + 30h: 45 is the starting fee (h = 0); 30 is the added cost per hour (the slope)
How many solutions?
ax + b = cx + d has one if a ≠ c, none if a = c and b ≠ d, infinitely many if a = c and b = d

5Systems & Linear Modelstwo equations, two unknowns

Elimination Worked

3x + 2y = 16 and x − 2y = 0
add: 4x = 16 → x = 4, then y = 2the y-terms cancel

Substitution Worked

y = 2x − 1 and 3x + y = 19
3x + 2x − 1 = 19 → x = 4, y = 7replace y
xyy ≤ −½x + 2(0, 0) ✓
0 ≤ 2 is true, so shade the side with (0, 0).
xyy = 2x − 13x + y = 19(4, 7)
The solution is where the lines cross.

Set up a word problem Worked

Adult tickets $12, student $7; 50 tickets brought in $460
a + s = 50 and 12a + 7s = 460one equation per fact
12a + 7(50 − a) = 460 → 5a = 110 → a = 22, s = 28
How many solutions?
LinesSolutions
different slopesexactly one
same slope, different intercepts (parallel)none
same line (one equation is a multiple of the other)infinitely many
2x + 3y = 6 and 4x + ky = 5 have no solution when k = 6: same slope, but 4x + 6y = 12 ≠ 5.

Inequalities in two variables

  • Solid boundary for ≤ or ≥, dashed for < or >.
  • Test (0, 0): if it works, shade its side.
  • A system’s solutions are where the shadings overlap.
School
Launch
Algebra II · Units 1–9: Algebra II · with Algebra I, Geometry, Statistics and Trigonometry
Lesson: schoollaunch.org/courses/algebra2/ · Original School Launch material.
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College Entrance Math ReviewAlgebra II · Units 1–9 · continued

6Functionsnotation, graphs, transformations

Function language

Domain; range
all allowed inputs; all outputs
Zero; y-intercept
an x with f(x) = 0; the value f(0)
Average rate of change
f(b) − f(a)b − a: for x² from 1 to 4, 16 − 13 = 5

Evaluate and compose Worked

f(x) = x² − 3x, g(x) = 2x + 1
f(−2) = 4 + 6 = 10
f(g(1)) = f(3) = 0; g(f(1)) = g(−2) = −3inside first
Transformations
ChangeEffect on the graph of y = f(x)
f(x) + kup k (down if k < 0)
f(x − h)right h (f(x + h): left h)
−f(x); f(−x)reflect over the x-axis; over the y-axis
a·f(x)vertical stretch (a > 1) or shrink (0 < a < 1)
f(bx)horizontal shrink by a factor of b (b > 1)
xy(−2, −5)
Dashed y = x²; solid y = (x + 2)² − 5: left 2, down 5, so the vertex moves from (0, 0) to (−2, −5).

Inverse Worked

f(x) = 3x − 6: swap x and y, solve: f⁻¹(x) = x + 63
check: f(4) = 6 and f⁻¹(6) = 4 ✓

7Function Families & Graphsknow the shapes on sight

linear
quadratic
cubic
absolute value
square root
reciprocal
exponential
logarithm
Domain and range
FamilyDomainRangeKey feature
y = x, y = x³all realsall realsthrough (0, 0)
y = x²; y = ∣x∣all realsy ≥ 0vertex (0, 0)
y = √xx ≥ 0y ≥ 0starts at (0, 0)
y = 1xx ≠ 0y ≠ 0asymptotes x = 0, y = 0
y = 2ˣall realsy > 0asymptote y = 0; (0, 1)
y = log₂ xx > 0all realsasymptote x = 0; (1, 0)

Reading a graph

  • f(a) is the height of the graph at x = a.
  • Solutions of f(x) = k: the x-values where the graph meets the line y = k.
  • f(x) > 0 where the graph is above the x-axis.
  • Number of real zeros = number of x-intercepts.

More function terms

Vertical line test
a graph is a function if no vertical line meets it twice
Piecewise
different rules on different intervals: f(x) = x + 1 for x < 2, 7 − x for x ≥ 2 gives f(1) = 2, f(4) = 3
Increasing
rises left to right; decreasing falls

Domain from a formula Worked

g(x) = 1x + 1: x ≠ −1no zero denominator
h(x) = √(x − 4): x ≥ 4no negative under √
k(x) = ln(x − 2): x > 2log of a positive

8Quadraticsthree forms, roots, vertex

Three forms
FormEquationShows
Standardax² + bx + cy-intercept c; axis x = −b2a
Vertexa(x − h)² + kvertex (h, k)
Factoreda(x − r)(x − s)zeros r and s; axis halfway
a > 0 opens up (minimum); a < 0 opens down (maximum).

Vertex and tangency Worked

y = −2x² + 8x + 1: x = −8−4 = 2, y = 9 (maximum)
y = 2x + k touches y = x² once when x² − 2x − k = 0 has 4 + 4k = 0: k = −1discriminant = 0

Quadratic formula

Discriminant b² − 4ac: > 0 two real roots, = 0 one (double) root, < 0 no real roots (two complex).

x = −b ± √(b² − 4ac)2a

Solve three ways Worked

2x² − 3x − 5 = 0 → (2x − 5)(x + 1) = 0 → x = 52 or −1factor
x² + 6x + 2 = 0 → (x + 3)² = 7 → x = −3 ± √7complete the square
x² − 4x + 1 = 0 → x = 4 ± √122 = 2 ± √3formula
xy−13(1, −4)
y = x² − 2x − 3: zeros −1 and 3; vertex (1, −4) on the axis x = 1; y-intercept −3.

Sum and product of roots

  • Sum = −ba; product = ca.

EX2x² − 3x − 5: sum 32, product −52 (check: 52 + (−1), 52 × (−1)).

School
Launch
Algebra II · Units 1–9: Algebra II · with Algebra I, Geometry, Statistics and Trigonometry
Lesson: schoollaunch.org/courses/algebra2/ · Original School Launch material.
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College Entrance Math ReviewAlgebra II · Units 1–9 · continued

9Exponents, Polynomials & Radicalsequivalent expressions and equations

Exponents and radicals
RuleExampleRuleExample
aᵐ · aⁿ = aᵐ⁺ⁿx³ · x⁴ = x⁷a⁰ = 1; a⁻ⁿ = 1aⁿ5⁻² = 125
aᵐaⁿ = aᵐ⁻ⁿx⁹x³ = x⁶am/n = (ⁿ√a)ᵐ82/3 = 4; 27−1/3 = 13
(aᵐ)ⁿ = aᵐⁿ; (ab)ⁿ = aⁿbⁿ(2x³)² = 4x⁶√(ab) = √a · √b√72 = 6√2
Factoring patterns
PatternFactored
a² − b²(a + b)(a − b)
a² + 2ab + b²; a² − 2ab + b²(a + b)²; (a − b)²
a³ + b³; a³ − b³(a + b)(a² − ab + b²); (a − b)(a² + ab + b²)
x³ + 2x² − 9x − 18 (grouping)(x + 2)(x + 3)(x − 3)

Remainder and factor theorems

  • p(x) ÷ (x − a) leaves remainder p(a).
  • (x − a) is a factor exactly when p(a) = 0.

EXp(x) = x³ − 4x² + x + 6: p(2) = 0, so p(x) = (x − 2)(x² − 2x − 3) = (x − 2)(x − 3)(x + 1).

Radical equation Worked

√(x + 7) = x + 1 → x + 7 = x² + 2x + 1 → x² + x − 6 = 0square both sides
x = 2 or −3; x = −3 gives √4 = −2 ✗, so x = 2check each root

Rational expressions Worked

x² − 9x² + x − 6 = (x − 3)(x + 3)(x + 3)(x − 2) = x − 3x − 2x ≠ −3, 2
x²x − 2 = 4x − 2 → x² = 4 → x = ±2; x = 2 divides by 0, so x = −2extraneous root

Check in the original

  • Squaring both sides or clearing denominators can add roots that do not work.

10Polynomial & Rational Graphszeros, end behavior, asymptotes

xy−124
y = (x + 1)(x − 2)² crosses at −1 (single zero) and touches at 2 (double zero); y-intercept 4.
End behavior
Leading termLeft endRight end
even degree, a > 0upup
even degree, a < 0downdown
odd degree, a > 0downup
odd degree, a < 0updown

Zeros and multiplicity

  • A factor (x − r) gives a zero at x = r.
  • Odd multiplicity: the graph crosses. Even multiplicity: it touches and turns back.
xy−1
y = x + 1x − 2: vertical asymptote x = 2, horizontal asymptote y = 1, zero at −1.

Rational functions

Vertical asymptote
a zero of the denominator that does not cancel
Hole
a factor that cancels: (x − 3)(x + 1)x − 3 has a hole at x = 3
Horizontal asymptote
degree top < bottom: y = 0; equal: y = ratio of leading coefficients; top > bottom: none

11Exponential Models & Logarithmsgrowth, decay, logs

Exponential model

a = starting amount; b > 1 grows by r = b − 1 per step; 0 < b < 1 decays.

y = a · bˣ = a(1 ± r)ᵗ

Models Worked

$2,000 at 5 % a year for 3 years: 2,000(1.05)³ = $2,315.25
600 mg, losing 20 % per hour, after 2 h: 600(0.8)² = 384 mg
50 cells doubling every 4 h: 50 · 2t/4; at t = 12, 400

Linear or exponential?

Linear
adds the same amount each step: 5, 8, 11, 14 (differences 3)
Exponential
multiplies by the same factor: 3, 6, 12, 24 (ratios 2)

Compound interest

Second form: continuous. $1,000 at 6 % monthly for 2 years: 1,000(1.005)²⁴ ≈ $1,127.16.

A = P(1 + rn)ⁿᵗ

A = Peʳᵗ

Logarithms (ACT, CLEP)
Log ruleExample
logb x = y means bʸ = xlog₂ 32 = 5; log₃ 19 = −2
log(xy) = log x + log ylog 4 + log 25 = log 100 = 2
log(x/y) = log x − log ylog₂ 48 − log₂ 3 = log₂ 16 = 4
log(xⁿ) = n log xlog 10⁵ = 5
logb x = ln xln b3ˣ = 20 → x = ln 20ln 3 ≈ 2.727
School
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Algebra II · Units 1–9: Algebra II · with Algebra I, Geometry, Statistics and Trigonometry
Lesson: schoollaunch.org/courses/algebra2/ · Original School Launch material.
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College Entrance Math ReviewAlgebra II · Units 1–9 · continued

12Ratios, Rates, Percents & Unitsproportional reasoning

Percent

part = percent × whole

% change = new − oldold × 100

Percent problems Worked

$80 jacket, 25 % off, then 8 % tax: 80(0.75)(1.08) = $64.80
Up 20 %, then down 20 %: 1.2 × 0.8 = 0.96 → 4 % lowernot back to even
After a 15 % raise the pay is $27.60/h; before: 27.60 ÷ 1.15 = $24.00divide by the multiplier

Percent shortcuts

  • 10 %: move the decimal point one place left; 5 % is half of that.

EX15 % tip on $42: 4.20 + 2.10 = $6.30.

Multiply by the multiplier

Up 7 % means × 1.07; down 7 % means × 0.93. Chain several changes by multiplying the multipliers.

Ratios and variation

  • a : b = 3 : 5 means a = 3k and b = 5k (total 8k).
  • Direct variation y = kx; inverse variation y = kx.

EXSplit 96 in a 3 : 5 ratio: k = 12, so 36 and 60. Inverse: y = 12 when x = 3 gives k = 36, so y = 4 at x = 9.

Units Worked

60 mi/h = 60 × 5,280 ft3,600 s = 88 ft/scancel units
3 ft × 4 ft = 36 in × 48 in = 1,728 in²1 ft² = 144 in²
250 g in 100 cm³: density 2.5 g/cm³
Equivalents to know
FractionDecimalPercent
18; 150.125; 0.212.5 %; 20 %
14; 130.25; 0.3̄25 %; 3313 %
12; 230.5; 0.6̄50 %; 6623 %
34; 320.75; 1.575 %; 150 %

Proportions and rates Worked

3 cups of flour for 24 cookies; for 60: 3 × 6024 = 7.5 cups
18 oz for $4.50 ($0.25/oz) or 24 oz for $5.76 ($0.24/oz): 24 oz is cheaper per ounceunit price
map 1 in : 15 mi; 3.2 in = 48 mi

Time and rate conversions Worked

$3.20 per pound = 3.20 ÷ 16 = $0.20 per ounce
2.25 h = 2 h 15 min; 135 min = 2.25 h0.25 h = 15 min

13Word Problems & Modelingturn words into equations

Translate
WordsMathWordsMath
is, equals=of (with a percent)×
more than, increased by+per, for each÷ (a rate)
less than, fewer−at least; at most≥; ≤
5 less than xx − 5twice the sum of x and 32(x + 3)

Distance, rate, time

Two cars leave the same town in opposite directions at 50 and 60 mi/h: they are 330 mi apart after 330 ÷ 110 = 3 h.

d = rt

Mixture Worked

How many liters of 40 % acid with 6 L of 10 % acid make a 20 % mix?
0.40x + 0.10(6) = 0.20(x + 6) → 0.2x = 0.6 → x = 3 Lacid in = acid out

Money Worked

Simple interest I = Prt: $1,500 at 4 % for 3 years = $180
6 % commission on a $240,000 sale = $14,400
$18 after a 25 % markup: cost = 18 ÷ 1.25 = $14.40

Work together Worked

A fills a tank in 3 h, B in 6 h: 13 + 16 = 12 tank per hour → 2 hadd the rates

Integers and ages Worked

Three consecutive even integers sum to 78: 3n + 6 = 78 → 24, 26, 28n, n + 2, n + 4
Ana is 3 times Ben’s age; in 8 years she will be twice his: 3b + 8 = 2(b + 8) → Ben 8, Ana 24

Interpret the pieces

  • In y = mx + b: m is the rate, b the starting value.
  • In y = a(b)ˣ: a is the start, b the growth factor per period.
  • In h = −16t² + vt + h₀: v is the launch speed, h₀ the launch height.

Build a model Worked

A plan costs $25 plus $0.10 per text: C = 25 + 0.10t; at 340 texts, C = $59linear
A town of 8,000 grows 3 % a year: P = 8,000(1.03)ᵗ; after 10 years ≈ 10,751exponential
A ball thrown up at 48 ft/s from 5 ft: h = −16t² + 48t + 5; highest at t = 1.5 s, h = 41 ftquadratic
xy(1.5, 41)5
h = −16t² + 48t + 5: the vertex (1.5, 41) is the highest point; the graph starts at 5 ft.
School
Launch
Algebra II · Units 1–9: Algebra II · with Algebra I, Geometry, Statistics and Trigonometry
Lesson: schoollaunch.org/courses/algebra2/ · Original School Launch material.
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College Entrance Math ReviewAlgebra II · Units 1–9 · continued

14Statistics & Datacenter, spread, displays

Center and spread

Mean; median
sum ÷ count; middle value in order (mean of the two middles if even)
Mode; range
most frequent value; largest − smallest
Standard deviation
typical distance from the mean: bigger means more spread
IQR; outlier
Q3 − Q1; a value beyond 1.5 × IQR from Q1 or Q3

Changing every value

  • Add c: mean and median go up by c; range and SD stay the same.
  • Multiply by c: mean, median, range and SD are all multiplied by c.

One data set Worked

2, 4, 4, 5, 7, 9, 11: mean 6, median 5, mode 4, range 9
add 30: mean 728 = 9, median 5 + 72 = 6an outlier pulls the mean
mean of 5 scores is 85; four are 80, 92, 75, 88 → fifth = 425 − 335 = 90total = mean × count
Displays
DisplayRead it for
Histogram; dot plotshape (symmetric, skewed), center, gaps
Box plotmin, Q1, median, Q3, max; IQR = box width
Scatterplotdirection, form, strength, outliers
Two-way tablecounts by two categories (§15)
556065707580859001234567residualŷ = 58.1 + 4.6xhours studied (x) vs quiz score (y)
Strong positive linear association. Slope 4.6: about 4.6 more points per hour. At x = 2 the line predicts 67.3, so the point (2, 70) has residual 70 − 67.3 = 2.7.
24 outlierQ1 6Q3 11median 81160510152025
Q1 = 6, median 8, Q3 = 11, IQR 5; fences −1.5 and 18.5, so 24 is an outlier.

15Probability & Inferencetwo-way tables, samples, studies

A two-way table (original data)
Lunch choiceHotPackedTotal
Grade 9421860
Grade 10303060
Total7248120

Read it Worked

P(hot) = 72120 = 0.6whole table
P(hot ∣ grade 10) = 3060 = 0.5grade 10 row only
P(grade 10 ∣ packed) = 3048 = 0.625packed column only

Probability rules

  • P(not A) = 1 − P(A).
  • Independent events: P(A and B) = P(A) · P(B).
  • P(A or B) = P(A) + P(B) − P(A and B).

EXTwo heads and then a 6: 14 × 16 = 124.

Estimate from a sample Worked

58 % ± 4 % → between 54 % and 62 %
46 of 200 sampled prefer A; of 5,000 people, expect 5,000 × 46200 = 1,150same proportion

Sampling and studies

Random sample
results can be generalized to the population sampled
Random assignment
needed to conclude cause and effect
Observational study
shows association, not cause
Margin of error
estimate ± MOE is the plausible range; larger samples give smaller margins

16Lines, Angles & Trianglesangles, similarity, Pythagoras

Angle facts

  • Vertical angles are equal; a linear pair sums to 180°.
  • Parallel lines and a transversal: corresponding and alternate interior angles are equal; same-side interior angles sum to 180°.
  • Triangle angles sum to 180°; an exterior angle equals the two remote interior angles together.
  • Polygon with n sides: interior angles sum to (n − 2) · 180° (hexagon 720°).
xxx√245°45°x√3x2x30°60°
The two special right triangles.

Similar triangles Worked

Corresponding sides are proportional; angles are equal
a 6-ft post casts a 4-ft shadow; a tree casts 18 ft: 64 = h18 → h = 27 ft
scale factor k: lengths × k, areas × k², volumes × k³k = 3: area × 9

Special right triangles Worked

30-60-90, hypotenuse 10: legs 5 and 5√3 ≈ 8.66
45-45-90, leg 7: hypotenuse 7√2 ≈ 9.90
square with diagonal 12: side 12√2 = 6√2
Triangle toolkit
FactDetail
Pythagorean theorema² + b² = c² (c is the hypotenuse)
Common triples3-4-5, 5-12-13, 8-15-17, 7-24-25 and multiples (6-8-10)
Triangle inequalityeach side < the sum of the other two: sides 4 and 9 → third between 5 and 13
Isoscelesequal sides face equal angles
School
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Algebra II · Units 1–9: Algebra II · with Algebra I, Geometry, Statistics and Trigonometry
Lesson: schoollaunch.org/courses/algebra2/ · Original School Launch material.
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College Entrance Math ReviewAlgebra II · Units 1–9 · continued

17Area, Volume & Circlesformulas and circle equations

Area and volume
FigureFormulaFigureFormulaSolidVolume
RectangleA = lwCircleA = πr²; C = 2πrBoxV = lwh
TriangleA = 12bhSectorA = θ360° · πr²CylinderV = πr²h
ParallelogramA = bhArc lengths = θ360° · 2πr = rθ (radians)Cone; pyramidV = 13πr²h; 13Bh
TrapezoidA = 12(b₁ + b₂)hRectangular boxsurface 2(lw + lh + wh)SphereV = 43πr³; S = 4πr²

Circle equation

center (h, k), radius r. Complete the square: x² + y² − 6x + 4y − 12 = 0 → (x − 3)² + (y + 2)² = 25: center (3, −2), r = 5.

(x − h)² + (y − k)² = r²

100°50°arc 100°
A central angle equals its arc; an inscribed angle is half of it (100° and 50° here), so one on a diameter is 90°. A tangent is perpendicular to the radius.

Worked Worked

r = 6, θ = 120°: arc = 4π ≈ 12.57; sector = 12π ≈ 37.70
cylinder r = 3, h = 8: 72π ≈ 226.19; sphere r = 3: 36π ≈ 113.10
(−2, 1) to (4, 9): distance √(36 + 64) = 10; midpoint (1, 5)d = √((Δx)² + (Δy)²)

18TrigonometrySOH-CAH-TOA, radians, unit circle

θadjacent 4opposite 3hypotenuse 5
Label the sides from θ’s point of view.

Right-triangle ratios

  • sin θ = oppositehypotenuse, cos θ = adjacenthypotenuse, tan θ = oppositeadjacent

EXIn the figure: sin θ = 35, cos θ = 45, tan θ = 34.

SOH-CAH-TOA (Traditional)

Sine = Opposite ÷ Hypotenuse, Cosine = Adjacent ÷ Hypotenuse, Tangent = Opposite ÷ Adjacent.

Cofunctions and identity

  • sin x° = cos(90° − x°): sin 28° = cos 62°.
  • sin²θ + cos²θ = 1.

Radians

135° = 3π4; 5π6 = 150°. Unit circle: the point at angle θ is (cos θ, sin θ).

π radians = 180°

Exact values
θ0°30°45°60°90°
sin θ012√22√321
cos θ1√32√22120
tan θ0√331√3undefined

ACT extras

Law of sines
asin A = bsin B = csin C
Law of cosines
c² = a² + b² − 2ab cos C
y = A sin(Bx) + D
amplitude ∣A∣, period 2π∣B∣, midline y = D: y = 3 sin 2x + 1 has amplitude 3, period π, range −2 to 4

19Number & Quantity (ACT, CLEP)beyond the SAT list

Complex numbers Worked

i = √−1, i² = −1; powers repeat every 4: i²³ = i³ = −i
(3 + 2i)(1 − 4i) = 3 − 12i + 2i − 8i² = 11 − 10i
5 + 5i1 + 2i · 1 − 2i1 − 2i = 15 − 5i5 = 3 − imultiply by the conjugate
Sequences
Arithmetic (add d)Geometric (multiply by r)
nth termaₙ = a₁ + (n − 1)daₙ = a₁rⁿ⁻¹
Sum of n termsSₙ = n(a₁ + aₙ)2Sₙ = a₁(1 − rⁿ)1 − r
Example7, 11, 15, …: a₂₀ = 83; S₂₀ = 9003, 6, 12, …: a₈ = 384

More ACT topics

Matrices
add entry by entry; multiply row by column; the determinant of rows (a, b), (c, d) is ad − bc
Vectors
⟨a, b⟩ has length √(a² + b²): ⟨−5, 12⟩ has length 13
Ellipse
x²a² + y²b² = 1: vertices (±a, 0), co-vertices (0, ±b)

Matrix work Worked

det of rows (2, 1) and (3, 4) = 2 · 4 − 1 · 3 = 5
rows (1, 2), (0, 1) times column (3, 4) = column (11, 4)row · column

Counting

  • Permutations (order matters): ₙPᵣ = n!(n − r)!.
  • Combinations (order does not): ₙCᵣ = n!r!(n − r)!.

EX8 runners, gold-silver-bronze: 8 · 7 · 6 = 336. A 3-person committee from 8: 56.

School
Launch
Algebra II · Units 1–9: Algebra II · with Algebra I, Geometry, Statistics and Trigonometry
Lesson: schoollaunch.org/courses/algebra2/ · Original School Launch material.
Page 7
of 8
College Entrance Math ReviewAlgebra II · Units 1–9 · continued

20Formulas to Know Coldthe ACT gives no sheet

Formula summary
TopicFormulaTopicFormulaTopicFormula
Slopem = y₂ − y₁x₂ − x₁Quadratic formulax = −b ± √(b² − 4ac)2aCircle(x − h)² + (y − k)² = r²
Liney = mx + bVertexx = −b2aArc; sectorθ360 · 2πr; θ360 · πr²
Distance√((x₂ − x₁)² + (y₂ − y₁)²)Growth or decayy = a(1 ± r)ᵗPythagoreana² + b² = c²
Midpoint(x₁ + x₂2, y₁ + y₂2)InterestA = P(1 + rn)ⁿᵗSpecial trianglesx, x, x√2; x, x√3, 2x
Percent changenew − oldold × 100Arithmeticaₙ = a₁ + (n − 1)dSOH-CAH-TOAopphyp, adjhyp, oppadj
MeansumcountGeometricaₙ = a₁rⁿ⁻¹Cylinder; coneπr²h; 13πr²h
ProbabilityfavorabletotalCombinationsₙCᵣ = n!r!(n − r)!Sphere43πr³; 4πr²
Common mistakes
MistakeFixMistakeFix
(a + b)² = a² + b²(a + b)² = a² + 2ab + b²√(9 + 16) = 3 + 4√25 = 5, not 7
−3² = 9−3² = −9; (−3)² = 9x² = 25 → x = 5x = ±5
a + ba = ba + ba = 1 + baup 20 %, down 20 % = no change1.2 × 0.8 = 0.96: 4 % less
flipping ≤ after × by a positiveflip only for a negativetrig in the wrong modecheck degrees or radians first

21Practice Setoriginal problems, answers checked

Thirty-four practice problems (original; not from any test)
#ProblemAnswer#ProblemAnswer
1(Algebra) Solve 5x − 7 = 2x + 11x = 69(Adv. math) Simplify x² − 16x + 4x − 4 (plug in x = 1: −3)
2(Algebra) Line through (1, −2) and (4, 7)y = 3x − 510(Data) $60, up 10 %, then down 10 %$59.40
3(Algebra) x + y = 10 and x − y = 4(7, 3)11(Data) Mean of 6, 9, 10, 15 and x is 11; find x15
4(Algebra) For which c does 3x + 6 = 3x + c have infinitely many solutions?c = 612(Data) From the §15 table, P(packed ∣ grade 9)0.3
5(Adv. math) Zeros of x² − 5x − 147 and −213(Geometry) Right triangle with legs 9 and 12: hypotenuse15 (3-4-5 × 3)
6(Adv. math) Vertex of y = 2(x − 3)² + 5(3, 5), minimum 514(Geometry) Center and radius of x² + y² + 8x − 2y = 8(−4, 1), r = 5
7(Adv. math) f(x) = 4x − 1; find f(f(2))2715(Trig) sin A = 513 in a right triangle; cos A and tan A1213; 512
8(Adv. math) Solve 2x + 1 = 32x = 4 (backsolve: 2⁵ = 32)16(ACT) (2 − 3i)(2 + 3i)13
Eighteen more
#ProblemAnswer#ProblemAnswer
17(Numbers) GCF and LCM of 18 and 246; 7226(Geometry) Arc length, r = 9, central angle 40°2π ≈ 6.28
18(Numbers) (4 × 10⁵)(5 × 10⁻²) in scientific notation2 × 10⁴27(Trig) Convert 210° to radians7π6
19(Algebra) Solve −3(x + 2) < 9x > −528(ACT) 5th term of 2, 6, 18, …; ₆C₂162; 15
20(Algebra) Slope of a line perpendicular to 4x − 2y = 7−1229(Algebra) 3x + 2y = 12 and x − y = −1(2, 3)
21(Adv. math) Number of real solutions of x² + 4x + 5 = 0none (discriminant −4)30(Adv. math) Simplify (3x²y)³27x⁶y³
22(Adv. math) Solve √(2x + 1) = 5x = 1231(Adv. math) Zeros of y = x(x − 4)²: cross or touch?0 crosses; 4 touches
23(Data) A $250 bike is marked down to $200; percent decrease20 %32(Adv. math) Horizontal asymptote of y = 6x + 12x − 5y = 3
24(Data) Pipe A fills a pool in 4 h, pipe B in 12 h; together3 h33(Data) Mean and median of 4, 8, 8, 10, 2010; 8
25(Geometry) Interior angle sum of an octagon1,080°34(Geometry) Volume of a cone, r = 3, h = 412π ≈ 37.70